AndroidX技术栈之二叉树
二叉树的遍历算法
package com.liu;
/**
* Created by befairyliu on 2018/7/16.
*/
public class TreeNode {
public TreeNode left;
public TreeNode right;
public int data;
public TreeNode(TreeNode left, TreeNode right, int data) {
this.left = left;
this.right = right;
this.data = data;
}
public TreeNode getLeft() {
return left;
}
public void setLeft(TreeNode left) {
this.left = left;
}
public TreeNode getRight() {
return right;
}
public void setRight(TreeNode right) {
this.right = right;
}
}
//======================class 分割线==============================
package com.liu;
import java.util.ArrayDeque;
import java.util.Queue;
import java.util.Stack;
/**
* Created by befairyliu on 2018/7/16.
*/
public class BinaryTree {
/*
* 前序遍历,非递归实现
* 1,先入栈根节点,输出根节点val值,再先后入栈其右节点、左结点;
* 2,出栈左节点,输出其val值,再入栈该左节点的右节点、左节点;直到遍历完该左节点所在子树。
* 3,再出栈右节点,输出其val值,再入栈该右节点的右节点、左节点;直到遍历完该右节点所在子树。
*/
public void preOrder(TreeNode root) {
Stack<TreeNode> stack = new Stack<>();
if (root != null) {
stack.push(root);
}
while (!stack.empty()) {
TreeNode node = stack.pop();
System.out.print(node.data);
//右结点先入栈,左结点后入栈
if (node.right != null) {
stack.push(node.right);
}
if (node.left != null) {
stack.push(node.left);
}
}
}
/*
* 中序遍历,非递归实现
* 1,首先从根节点出发一路向左,入栈所有的左节点;
* 2,出栈一个节点,输出该节点val值,查询该节点是否存在右节点,
* 若存在则从该右节点出发一路向左入栈该右节点所在子树所有的左节点;
* 3,若不存在右节点,则出栈下一个节点,输出节点val值,同步骤2操作;
* 4,直到节点为null,且栈为空。
*/
public void midOrder(TreeNode root) {
Stack<TreeNode> stack = new Stack<>();
while (root != null || !stack.empty()) {
while(root != null){
stack.push(root);
root = root.left;
}
if(!stack.empty()){
TreeNode node = stack.pop();
System.out.print(node.data);
root = node.right;
}
}
}
//后序遍历
public void afterOrder(TreeNode root){
if(root != null){
afterOrder(root.right);
afterOrder(root.left);
System.out.print(root.data);
}
}
//层序遍历(广度优先遍历)
public void layerOrder(TreeNode root){
Queue<TreeNode> queue = new ArrayDeque<>();
if(root != null){
queue.offer(root);
}
while (!queue.isEmpty()){
TreeNode node = queue.poll();
System.out.print(node.data);
if(node.left != null){
queue.offer(node.left);
}
if(node.right != null){
queue.offer(node.right);
}
}
}
}